Determine whether a character is a number in Java
Nov 19, 2019 pm 02:24 PM一、使用自帶函數(shù)isDigit()
語法:
public static boolean isDigit(char ch)
實例:
public static boolean isNumeric (String str) { for (int i = str.length(); --i >=0) { if (!Character.isDigit(str.charAt(i))) { return false; } } return true;}
二、使用正則表達式
實例1:
public static boolean isNumeric(String str) { Pattern pattern = Pattern.compile("^[-\\+]?[\\d]*$"); return pattern.matcher(str).matches();}
實例2:
public static boolean isNumeric(String str) { if (str != null && !"".equals(str.trim())) { return s.matches("^[0-9]*$"); } return false;}
實例3:
public static boolean isNumeric (String str) { Pattern pattern = Pattern.compile("[0-9]*"); return pattern.matcher(str).matcher();}
三、使用ASCII碼
public static boolean isNumeric (String str) { for (int i = str.length(); --i>=0;) { int chr = str.charAt(i); if (chr < 48 || chr > 57) { return false; } } return true;}
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