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Table of Contents
? Use the copy() built-in function
?? Common ways to copy a slice
? Important notes
? What doesn't work
? Summary: Best practice
Home Backend Development Golang how to properly copy a slice in go

how to properly copy a slice in go

Jul 30, 2025 am 01:28 AM
go 切片復(fù)制

To correctly copy slices in Go, you must create a new underlying array instead of directly assigning values; 1. Use make and copy functions: dst := make([]T, len(src)); copy(dst, src); 2. Use append and nil slices: dst := append([]T(nil), src...); both methods can achieve element-level copying, avoid sharing the underlying array, and ensure that modifications do not affect each other. Direct assignment of dst = src will cause both to refer to the same array and are not real copying.

how to properly copy a slice in go

In Go, copying a slice isn't always as straightforward as assigning one variable to another—because slices are reference types. If you just assign a slice to a new variable, both will refer to the same underlying array. So, to properly copy a slice , you need to create a new slice and copy the elements into it. Here's how to do it correctly.

how to properly copy a slice in go

? Use the copy() built-in function

The idiomatic and safest way to copy a slice in Go is using the built-in copy() function:

 src := []int{1, 2, 3}
dst := make([]int, len(src))
copy(dst, src)

Now dst is a separate slice with the same values as src , but modifications to one won't affect the other.

how to properly copy a slice in go

You can also combine it into one line:

 dst := make([]int, len(src))
copy(dst, src)

Or even more concisely:

how to properly copy a slice in go
 dst := append([]int(nil), src...)

This works because append will allocate new space when adding elements to a nil slice.


?? Common ways to copy a slice

Here are a few standard approaches:

  • Using make copy (recommended for clarity):

     dst := make([]T, len(src))
    copy(dst, src)
  • Using append with a nil slice:

     dst := append([]T(nil), src...)
  • Using copy into a slice of the same length: Make sure the destination has enough space— copy only copies up to the minimum of the two lengths.

    ?? This is a common mistake:

     dst := []int{} // len = 0
    copy(dst, src) // copyies 0 elements!

    So ensure dst has sufficient length or capacity.


? Important notes

  • copy() returns the number of elements copied (which is min(len(src), len(dst)) ), but you usually don't need this value.

  • If you want to preserve capacity (eg, for future appends), use:

     dst := make([]int, len(src), cap(src))
    copy(dst, src)
  • For slices of pointser or complex structs , this method still works, but remember: it's a shallow copy . The pointed-to data isn't duplicated.

    Example:

     type Person struct{ Name string }
    src := []*Person{{Name: "Alice"}}
    dst := make([]*Person, len(src))
    copy(dst, src)

    Now dst[0] and src[0] point to the same Person struct. Changing dst[0].Name affects the same object.

    To deep copy, you'd need to manually clone each element.


? What doesn't work

 dst := src // Just copies the slice header—both point to same data!
dst[0] = 99 // This modifies src[0] too!

This is not a copy—it's just another reference to the same underlying array.


? Summary: Best practice

To properly copy a slice:

 dst := make([]T, len(src))
copy(dst, src)

Or, if you prefer brevity and don't need to pre-allocate:

 dst := append([]T(nil), src...)

Both are safe, efficient, and commonly used in Go code.

Basically, just avoid direct assignment and make sure you're copying elements into a new backing array.

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