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Table of Contents
Specify format parsing: Use DateTime::createFromFormat
Handle different regional formats or locale environments
Tips: Get formatted results
Home Backend Development PHP Tutorial php convert string to DateTime object

php convert string to DateTime object

Jul 18, 2025 am 04:23 AM

There are two main ways to convert a string to a DateTime object in PHP. First, use new DateTime($time), which is suitable for standard formats such as '2025-04-05' or strings with time zones, but it needs to be handled with try-catch; second, use DateTime::createFromFormat('format', 'string'), which is used to parse non-standard formats such as '05/04/2025', where supported formats include Y (year), m (month), d (day), H (hour), i (minute), s (seconds), etc.; in addition, localized formats such as English month can be directly parsed, while non-English environments such as Chinese need to be preprocessed or extended with the help of intl; finally, the string in the specified format can be output through $date->format('Ym-d').

php convert string to DateTime object

In PHP, converting strings to DateTime objects is a common operation, especially when dealing with date and time-related logic. As long as the format is correct, it can be easily implemented using the built-in DateTime class.

php convert string to DateTime object

Basic usage: Use DateTime::__construct

The easiest way is to create an object through new DateTime($time) . where $time is a legal time string, such as:

php convert string to DateTime object
 $date = new DateTime('2025-04-05');

This method is suitable for most standard format strings, such as 'now' , '2023-12-31' or '2023-12-31 23:59:59 UTC' with time zone information.

If the format of the string you passed in is not recognized, PHP will throw an Exception , so it is recommended to use it with try-catch :

php convert string to DateTime object
 try {
    $date = new DateTime('not a valid date');
} catch (Exception $e) {
    echo "Date format error:" . $e->getMessage();
}

Specify format parsing: Use DateTime::createFromFormat

If your date string format is special, such as "05/04/2025" (day/month/year), using the constructor directly may cause errors or parse into an incorrect format. At this time, you should use:

 $date = DateTime::createFromFormat('d/m/Y', '05/04/2025');

This method allows you to explicitly specify the format of the input string to ensure accurate parsing. Supported formats include:

  • Y four-digit year
  • m months
  • d date
  • H hours (24-hour system)
  • i minute
  • s seconds

You can adjust the format parameters according to the actual input, such as:

 $date = DateTime::createFromFormat('Ymd H:i:s', '2025-04-05 14:30:00');

Handle different regional formats or locale environments

Sometimes you may get a localized format, such as the English month name 'April 5, 2025' , which can be parsed normally by default:

 $date = new DateTime('April 5, 2025');

But if you are facing a non-English environment, such as Chinese month, you need to preprocess it first or use a third-party library such as intl extension to process localized dates.


Tips: Get formatted results

Once you have the DateTime object, you can easily output the format you need:

 echo $date->format('Ym-d'); // Output: 2025-04-05

Common format examples:

  • Ymd H:i:s full format
  • Y/m/d simple slash format
  • l, F j, Y English full week and month such as Saturday, April 5, 2025

Basically that's it. Master these methods and deal with various string conversion DateTime . The key is to select the appropriate method according to the input format and pay attention to exception handling to avoid program crashes.

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