(unofficial) test results, see for yourself

Number()

parseInt()

Math.floor()

Math.round()

Math.ceil()

|0

^0

-0

Math.floor+

-Math.floor-

--split[0]

+split[0]

+'123'

Math.floor(+'123.123');

-Math.floor(-'123.123')

-(-'123.213'.split('.')[0]);

+'123.213'.split('.')[0]

There are many conversion methods, but they are all small tricks of using operators for implicit conversion.

In addition to priority and associativity, please also note that different operands will affect the implicit conversion of operators.

There are also these methods,
'3.1425' | 0
'7.86'^0
'123'-0

I feel like the methods specifically used for conversion are faster, like parseInt and Number you mentioned. I haven’t tried it personally

var a = 1.123445;
a >> 0;

String inString = ""; // The inString variable is used to store the value from the input

Void setup () {
??// Open serial port with baudrate 9600
??Serial.begin (9600);
??While (! Serial) {
????; // wait Serial port is turned on (just with Arduino Leonardo circuit)
??}

??// Send a message that the setup function has finished
??Serial.println (" n nChanges compared to:");
??Serial.println ();
}

Void loop () {
??// Read the value from Serial
??While (Serial.available ()> 0) {
????Int inChar = Serial.read ();
????If (isDigit (inChar)) {// Check function NUMBER is a digital character
??????// and add strings. Otherwise you will add an integer to it: P
??????InString + = (char) inChar;
????}
????// If inChar is a newline character. I print the results
????If (inChar == ' n') {// One character uses '(single quote) and one string to use' (double quotes)
??????Serial.print ("value:");
??????Serial.println (inString.toInt ());
??????Serial.print ("string:");
??????Serial.println (inString);
??????// delete the value of the inString variable
??????InString = "";
????}
??}
}
photo editor

Also~~'123.45'

var a = '1'

var b = a * 1

b is number