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c++ - Question about forward_list using iterator to output elements
過去多啦不再A夢
過去多啦不再A夢 2017-05-31 10:39:45
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#include "iostream"
#include "forward_list"
#include "string"

using namespace std;

int main() {
    
    forward_list<int> fl1 = { 1, 2, 3 };
    for (auto iter = fl1.begin(); iter != fl1.end(); ++iter) {
        cout << *iter << " ";
    }
    cout << endl;
    //以上都是沒什么問題的,在控制臺會打印出1 2 3
    //但是……
    
    forward_list<string> fl2 = { "hello", "world", "Cpp" };
    for (auto iter = fl2.begin(); iter != fl2.end(); ++iter) {
        cout << *iter << " "; //這里VS報錯沒有對應(yīng)<<的元素, 請問這是為什么?
        //而且當(dāng)我用printf(%s, *iter)打印時雖然編譯器不報錯但是輸出的結(jié)果卻是亂碼……
    }
    cout << endl;

    return 0;
}
過去多啦不再A夢
過去多啦不再A夢

reply all(1)
PHPzhong

g++ 6.3.0 x86_64-posix-seh-rev2 No problem
clang++ 4.0.0 Target: x86_64-pc-windows-msvc No problem
In this case, use for(const auto& item : list) More OK.

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