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react-router傳遞參數(shù)無非通過url里面的動態(tài)匹配或者queryTo transfer, it is very clear in this document.

But in this login scenario, the better way is not to pass cookie來進行登錄態(tài)的確定，從而使域名下的任何一個網頁都能知道已經登錄，而不需要像這樣傳遞state.

Two ways:
The first one: put the state into a state machine through a redux-like idea, and take it as you want,
The second way: use history transfer (route jump), if you jump from route A to route B, Route B component wants to get the data from Route A. You can do this:

   class A extends React.Component{
      constructor(){ super(); }
      handleClick(){
          browserHistory.push({
             state:state //傳遞方式1 你需要傳遞的狀態(tài)
             query:query  //傳遞方式2  顯示在路由路徑當中的query串，路由B也可以接收;      
         })
      }
     render …………
   }
   
   class B extends React.Component{
      constructor(){
          super();
      }
      componentWillMount(){
          //當前傳遞過來的狀態(tài)
          console.log(this.props.location.state)
      }
      render…………
  }

Print this.props of the routing component and take a look. There are many things you need in it.

Use redux/flux to store login status
And use cookie/LocalStorage/SessionStorage to store user login information,
Otherwise, after refreshing the page, the status is still not logged in

You can use react-redux to store the relevant required parameters in the store, and then connect each sub-component. The parameters of the store can be used as props