A circle is a round shape two-dimensional diagram which has no corners. Every circle has an origin point and every point on the circle maintains equal distance from the origin. The distance between the origin and a point in a circle is known as Radius of the circle. And similarly, if we draw a line from one edge to another edge of the circle and the origin is held in the middle of it, that line is known as diameter of the circle. Basically, the diameter is double of the length of the radius.

A square consists of four sides and all the four sides have equal length. If we try to put a circle inside a square with maximum radius possible, then the diameter of the circle is equal to the length of the side of the square. So here we can conclude that the radius of the circle is equal to half of the square’s side length.

Area of the circle refers to the total surface area acquired by the circle. We can calculate the square of the circle by using radius and a constant known as π

Formula to calculate area of the circle ?

$$\mathrm{面積=\pi \times (半徑)^{2}}$$

由于圓被內(nèi)接在一個(gè)正方形中，所以圓的半徑（r）= 邊長(zhǎng)/2，其中‘邊長(zhǎng)’指的是正方形的邊長(zhǎng)。

$$\mathrm{Area \;of \; inscribed \;circle \;in \;square=\varpi\times(side/2)^{2}=\varpi\times(side^{2}/4)=(\varpi/4)^{*}sides^{2}}$$

在本文中，我們將看到如何找到內(nèi)接在正方形中的圓的面積

To show you some instances ?

Instance-1

The side length of the square given = 9
The area of the circle inscribed in square = (? / 4) * side2 = (3.141/4) * 9 * 9 = 63.605

Instance-2

The side length of the square given = 50
The area of the circle inscribed in square = (? / 4) * side2 = (3.141/4) * 50 * 50 =
1963.125

Instance-3

The side length of the square given = 32
The area of the circle inscribed in square = (? / 4) * side2 = (3.141/4) * 32 * 32 = 804.096

Algorithm

Step-1 ? Get the side length of the square either by static input or by user input.

Step-2 ? Find the area of the circle inscribed in a square by using the formula.

Step-3 ? Print the result.

Multiple Approaches

我們以不同的方法提供了解決方案。

• By Using Static Input Value.

• 通過使用具有靜態(tài)輸入值的用戶定義方法。

• 通過使用用戶定義的方法和用戶輸入的值。

Let’s see the program along with its output one by one.

途徑-1：通過使用靜態(tài)輸入值

在這種方法中，我們聲明一個(gè)雙精度變量，并將其初始化為正方形的邊長(zhǎng)。然后通過使用算法，我們可以找到內(nèi)切于正方形的圓的面積。

Example

import java.io.*;
public class Main {
   //main method
   public static void main (String[] args) {
      //declare a variable to store the value of pi
      double pi = 3.14;
      //declare a variable to store the value of side of the square
      float side = 15;
      //declare a variable to store the area of the circle
      //find area by using the formula
      double area = ( pi / 4 ) * side * side;
      System.out.println("Area of the circle inscribed in the square is: "+ area);
   }
}

Output

Area of the circle inscribed in the square is: 176.625

Approach-2: By Using User Defined Method with Static Input Value

In this approach, we declare a double variable and initialize the side length value of the square. Then by using the algorithm we can find the area of the circle inscribed in a square.

Example

import java.io.*;
public class Main {
   //declare a static variable to store the value of pi
   static double pi = 3.14;

   //main method
   public static void main (String[] args) {
      //declare a variable to store the value of side of the square
      float side = 15;
      System.out.println("Area of the circle inscribed in the square is: "+ areaOfCircle(side));
   }

   // user-defined method to find the area of the circle
   static double areaOfCircle(float side) {
      return ( pi / 4 ) * side * side;
   }
}

Output

Area of the circle inscribed in the square is: 176.625

Approach-3: By Using User Defined Method with User Input Value

在這種方法中，我們聲明一個(gè)雙精度變量，并獲取用戶輸入的正方形的邊長(zhǎng)。然后通過使用算法，我們可以找到內(nèi)切于正方形的圓的面積。

Example

import java.io.*;
import java.util.*;
public class Main {
   //declare a static variable to store the value of pi
   static double pi = 3.14;

   //main method
   public static void main (String[] args) {
      //Create object of Scanner class
      Scanner sc= new Scanner(System.in);
      System.out.print("Enter the length of side of the square: ");
      //declare a variable to store the value of side of the square
      double side = sc.nextDouble();
      System.out.println("Area of the circle inscribed in the square is: "+
      areaOfCircle(side));
   }

   // user-defined method to find the area of the circle
   static double areaOfCircle(double side) {
      return ( pi / 4 ) * side * side;
   }
}

Output

Enter the length of side of the square: 9
Area of the circle inscribed in the square is: 63.585

In this article, we explored how to find the area of a circle inscribed in a square in Java by using different approaches.

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