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What is the execution order of static code blocks, construction code blocks, and construction methods?
What is the execution order of static code blocks, construction code blocks, and construction methods?
Jan 25, 2022 am 11:41 AM
The execution order is: first execute the "static code block", then execute the "constructed code block", and finally execute the "constructed code block". Static code blocks are at the class level, while structural code blocks and construction methods are at the instance level, so the static code blocks are executed first; and because the structural code blocks are independent and must rely on a carrier to run, the structural code blocks need to be placed in the structure before method.
The operating environment of this tutorial: windows7 system, java8 version, DELL G3 computer.
Construction code block, static code block and construction method are three different code blocks in the class, so what are the differences between them?
1. Introduction to three types of code blocks
Static code block: declared with staitc, executed when jvm loads the class, only executed once
Constructed code block: directly used in the class {} definition, executed every time an object is created.
Execution order priority: static block, main(), construction block, construction method.
class A
{
//構(gòu)造代碼塊
{
System.out.println("構(gòu)造代碼塊A");
}
//靜態(tài)代碼塊
static
{
System.out.println("靜態(tài)代碼塊A");
}
//構(gòu)造方法
public A()
{
System.out.println("構(gòu)造方法A");
}
}The execution order of the second and third parties
In order to clarify the execution order of the three, we instantiate class A and test single instances and multiple instances respectively.
2.1 Single instance
class Demo
{
public static void main(String[] args)
{
new A();
}
}
2.2 Multiple instances
class Demo
{
public static void main(String[] args)
{
new A();
new A();
new A();
}
}
3. The order in the inheritance system
class B extends A
{
//構(gòu)造代碼塊
{
System.out.println("構(gòu)造代碼塊B");
}
//靜態(tài)代碼塊
static
{
System.out.println("靜態(tài)代碼塊B");
}
//構(gòu)造方法
public B()
{
System.out.println("構(gòu)造方法B");
}
}
class Demo
{
public static void main(String[] args)
{
new B();
}
}
4. Summary
1. In the process of creating an object, the execution order of the three is: Static code block --> Construction code block --> Construction method;
1. Static code block: It is performed during the third step of initialization of the class loading process. Its main purpose is Is to assign an initial value to the class variable.
2. Construction code block: It is independent and must be attached to a carrier to run. Java will place the construction code block in front of each construction method to instantiate some common instance variables and reduce the amount of code.
3.Construction method: used to instantiate variables.1 is at the class level, 2 and 3 are at the instance level, so naturally 1 takes precedence over 23.
Let’s understand one thing: the active use of a subclass will lead to the active use of its parent class, so although the subclass is instantiated, it will also lead to the initialization and instantiation of the parent class, and it is optimal Executed in subclasses.
2. Every time an object is created, the construction code block and construction method will be executed once; no matter how many objects are created, the static code block will only be executed once when the first object is created;
3. When creating a subclass object, the static code block of the subclass is executed after the static code block of the parent class, but takes precedence over the construction code block and construction method of the parent class;
4. When creating a subclass object, The construction code block of the subclass is executed after the construction method of the parent class.
Recommended related video tutorials: Java video tutorial
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