java中判斷字符串是否是數字的方法如下:
1、用Java自帶的方法
Java中有一個Character.isDig(char ch)
????public?class?CheckStrIsNum?{??? ????????public?static?void?main(String[]?args)?{????? ????????????double?aa?=?-192322.1212;???? ????????????String?a?=?"-192322.1212";?? ????????????String?b?=?"-192322a1212";????? ????????????String?c?=?"Java";?? ????????????String?d?=?"5";???? ????????????/**?判斷是否全為數字?*/????????????????????? ????????????System.out.println(checkStrIsNum01(Double.toString(aa)));???????? ????????????System.out.println(checkStrIsNum01(a));???????? ????????????System.out.println(checkStrIsNum01(b));???????? ????????????System.out.println(checkStrIsNum01(c));???????? ????????????System.out.println(checkStrIsNum01(d));? ????????} ???????? ????????/** ?????????*?利用Java的character.isDigit方法進行處理 ?????????*/ ????????public?static?boolean?checkStrIsNum01(String?str)?{???? ????????????for?(int?i?=?0;?i?<?str.length();?i++)?{???? ????????????????System.out.println(str.charAt(i));? ????????????????if?(!Character.isDigit(str.charAt(i)))?{? ????????????????????return?false;?? ????????????????} ????????????}? ????????????return?true; ???????} ????}
顯然b應該返回false才對,但是卻返回true,而"5"應該返回true,也是結果錯誤。由此可見,這個結果,并不完美。
2、利用正則表達式來判斷
利用正則表達式來-?[0-9]+(\\.[0-9]+)?來做判斷字符串是否為數字。
如果傳入的數據有很多位,那么使用double會導致精度丟失,這個時候就要用BigDecimal來進行轉換。
????public?class?CheckStrIsNum?{??? ????????public?static?void?main(String[]?args)?{????? ????????????double?aa?=?-192322.1212;???? ????????????String?a?=?"-192322.1212";?? ????????????String?b?=?"-192322a1212";????? ????????????String?c?=?"Java";?? ????????????String?d?=?"5";???? ????????????/**?判斷是否全為數字?*/????????????????????? ????????????System.out.println(checkStrIsNum02(Double.toString(aa)));???????? ????????????System.out.println(checkStrIsNum02(a));???????? ????????????System.out.println(checkStrIsNum02(b));???????? ????????????System.out.println(checkStrIsNum02(c));???????? ????????????System.out.println(checkStrIsNum02(d));? ????????} ???????? ????????private?static?Pattern?NUMBER_PATTERN?=?Pattern.compile("-?[0-9]+(\\.[0-9]+)?"); ????????/**? ?????????*?利用正則表達式來判斷字符串是否為數字? ?????????*/ ?????????public?static?boolean?checkStrIsNum02(String?str)?{? ????????????String?bigStr;? ????????????try?{?????? ????????????????/**?先將str轉成BigDecimal,然后在轉成String?*/ ????????????????bigStr?=?new?BigDecimal(str).toString();? ????????????}?catch?(Exception?e)?{? ????????????????/**?如果轉換數字失敗,說明該str并非全部為數字?*/ ????????????????return?false;? ????????????}? ????????????Matcher?isNum?=?NUMBER_PATTERN.matcher(str);? ????????????if?(!isNum.matches())?{???? ????????????????return?false;? ????????????}?? ????????????return?true; ????????} ????}
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