java 基本數(shù)據(jù)類型最大值極限和最小值極限,寫個(gè)小程序就很容易知道。?
測試 integer, long, float 和 double 的最大值和最小值,代碼如下:?
? public static void main(string[] args)?
? {?
??? system.out.println("integer.min_value = " + integer.min_value);?
??? system.out.println("integer.max_value = " + integer.max_value);?
??? system.out.println("long.min_value = " + long.min_value);?
??? system.out.println("long.max_value = " + long.max_value);?
??? system.out.println("float.min_value = " + float.min_value);?
??? system.out.println("float.min_normal = " + float.min_normal);?
??? system.out.println("float.max_value = " + float.max_value);?
??? system.out.println("double.max_value = " + double.max_value);?
??? system.out.println("double.min_value = " + double.min_value);?
? }?
輸出結(jié)果如下:?
integer.min_value = -2147483648??? (10位)?
integer.max_value = 2147483647?
long.min_value = -9223372036854775808? (19位)?
long.max_value = 9223372036854775807?
float.min_value = 1.4e-45?
float.min_normal = 1.17549435e-38?
float.max_value = 3.4028235e38?
double.max_value = 1.7976931348623157e308?
double.min_value = 4.9e-324?
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