The answer is: Use the std::string constructor to convert the char array to std::string. If the array contains the intermediate '\0', the length must be specified. 1. For C-style strings ending with '\0', use std::string str(charArray); to complete the conversion; 2. If the char array contains the middle '\0' but needs to convert the first N characters, use std::string str(charArray, length); to clearly specify the length; 3. When processing fixed-size arrays, make sure it ends with '\0' and then convert it; 4. Use str.assign(charArray, charArray strlen(charArray)) or std::copy to achieve flexible assignment; 5. Since C 11, it supports implicit conversion of std::string str = charArray;; 6. Be careful to avoid uninitialized or unterminated '\0' The array of arrays is constructed without length, and it is recommended to explicitly pass lengths when processing external data to ensure security.
In C, converting char
array to std::string
is a common operation. As long as the char
array is a C-style string ending with null characters \0
(i.e. null-terminated string), the conversion is very simple.

Basic usage: directly construct string
The most direct way is to use the constructor of std::string
:
#include <iostream> #include <string> int main() { char charArray[] = "Hello, world!"; std::string str(charArray); // Automatically recognize \0 End std::cout << str << std::endl; // Output: Hello, world! return 0; }
This method works for all character arrays ending with \0
.

If the char array contains the intermediate '\0' (binary data)
If the char
array may contain \0
, but you still want to convert the first N characters (such as raw data read from the network or file), you should specify the length:
#include <iostream> #include <string> int main() { char charArray[] = {'H', 'e', 'l', 'l', 'o', '\0', 'W', 'o', 'r', 'l', 'l', 'd'}; int length = 11; // Contains the content after \0 std::string str(charArray, length); // Specifies the length and will not stop at \0 std::cout << "Length: " << str.length() << std::endl; // Output 11 std::cout << "Content: "; for (char c : str) { if (c == '\0') std::cout << "\\0"; // Show \0 else std::cout << c; } std::cout << std::endl; return 0; }
Output:

Length: 11 Content: Hello\0World
?? Note: In this case,
std::string
can save\0
, but it will be truncated at the first\0
when output withc_str()
.
Other common scenarios
1. Copy from a fixed-size array (safety practice)
char buffer[256]; strcpy(buffer, "Test message"); std::string str(buffer); // OK, as long as buffer ends with \0
2. Use std::copy
(more flexible)
char charArray[] = "Sample"; std::string str; str.assign(charArray, charArray strlen(charArray)); // or specify the length
3. Support direct initialization from C 11
std::string str = charArray; // Implicit conversion as long as charArray is char* or char[]
Things to note
- ?
char[]
must be valid and end with\0
(unless you pass the length). - ? Do not directly construct strings for arrays that are not initialized or ended with
\0
. - ? If you process user input or network data, it is recommended that the transmission length is safer.
Basically that's it. The most commonly used ones are:
std::string str(charArray);
As long as your char
array is a standard C string, this is enough to write.
The above is the detailed content of C char array to string example. For more information, please follow other related articles on the PHP Chinese website!

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