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Table of Contents
? 基本語(yǔ)法
? 示例:從 vector 中刪除所有偶數(shù)
? 說(shuō)明
? 再舉一例:刪除字符串中的空格
?? 注意事項(xiàng)
Home Backend Development C++ C std::remove_if example

C std::remove_if example

Jul 31, 2025 am 12:30 AM

std::remove_if不會(huì)真正刪除元素,而是將不滿(mǎn)足刪除條件的元素前移,并返回指向新邏輯末尾的迭代器,需配合erase()才能真正刪除元素;1. 使用std::remove_if時(shí)需傳入操作區(qū)間和返回bool的一元謂詞;2. 典型用法是“erase-remove慣用法”,如vector中刪除偶數(shù);3. 可用于字符串刪除空格等場(chǎng)景;4. 不適用于set、map等關(guān)聯(lián)容器;5. list容器應(yīng)使用其成員函數(shù)list::remove_if以提高效率。該方法是C++中條件刪除序列元素的標(biāo)準(zhǔn)做法,簡(jiǎn)潔且高效。

C++ std::remove_if example

std::remove_if 是 C++ 標(biāo)準(zhǔn)庫(kù)中 <algorithm> 頭文件提供的一個(gè)算法函數(shù),用于移除滿(mǎn)足特定條件的元素。需要注意的是,它并不會(huì)真正從容器中刪除元素(即不會(huì)改變?nèi)萜鞔笮。?,而是將不滿(mǎn)足條件的元素前移,返回一個(gè)指向新邏輯末尾的迭代器。通常需要配合 erase() 使用,才能真正刪除元素(這被稱(chēng)為“erase-remove 慣用法”)。

C++ std::remove_if example

? 基本語(yǔ)法

std::remove_if(iterator first, iterator last, UnaryPredicate pred);
  • first, last:操作范圍
  • pred:一元謂詞(返回 bool 的函數(shù)或 lambda),用于判斷是否“要移除”
  • 返回值:指向新邏輯末尾的迭代器

? 示例:從 vector 中刪除所有偶數(shù)

#include <iostream>
#include <vector>
#include <algorithm>

int main() {
    std::vector<int> nums = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

    // 使用 erase-remove 慣用法刪除所有偶數(shù)
    nums.erase(
        std::remove_if(nums.begin(), nums.end(), [](int n) {
            return n % 2 == 0;  // 返回 true 表示要移除
        }),
        nums.end()
    );

    // 輸出結(jié)果
    for (int n : nums) {
        std::cout << n << " ";
    }
    std::cout << std::endl;

    return 0;
}

輸出:

1 3 5 7 9

? 說(shuō)明

  • std::remove_if 把所有“不滿(mǎn)足刪除條件”的元素(這里是奇數(shù))移到前面。
  • 返回的迭代器指向“新末尾”,即第一個(gè)被“移走”位置。
  • erase() 從該位置到原末尾真正刪除元素。

? 再舉一例:刪除字符串中的空格

#include <iostream>
#include <string>
#include <algorithm>

int main() {
    std::string str = "Hello World This is C++";

    str.erase(
        std::remove_if(str.begin(), str.end(), [](char c) {
            return c == ' ';
        }),
        str.end()
    );

    std::cout << str << std::endl;  // 輸出: HelloWorldThisisC++
    return 0;
}

?? 注意事項(xiàng)

  • std::remove_if 不適用于關(guān)聯(lián)容器(如 set, map),因?yàn)樗鼈儍?nèi)部有序且不允許隨意重排。
  • 對(duì)于 list,推薦使用 list::remove_if 成員函數(shù),更高效:
    std::list<int> lst = {1, 2, 3, 4, 5};
    lst.remove_if([](int n) { return n % 2 == 0; });

    基本上就這些。std::remove_if 配合 erase() 是處理序列容器中“條件刪除”的標(biāo)準(zhǔn)做法,簡(jiǎn)潔又高效。

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