What is type erasure in Java generics?
Jul 23, 2025 am 12:15 AMJava's generic type erasure is the mechanism by which the compiler erases specific type information when processing generics. 1. Java will remove generic information during compilation, so that List
Type Erasure for Java is a key mechanism for Java compilers to handle generics. Simply put, it refers to Java "erase" generic information during compilation, and no longer keep records of specific type parameters at runtime . This means that List<string></string>
and List<integer></integer>
are actually the same type at runtime.

Why is this designed? Mainly to maintain compatibility with older versions of Java (no generics before 1.5). But this also brings some restrictions and things to pay attention to.
The basic principle of type erasing
Java generics were introduced in Java 5, and in order to enable new code to coexist with old code, Java uses a type erase mechanism. Its basic rules include:

- Generic types will be replaced with their boundary types after compilation , such as
T
being replaced withObject
. - If there is a limitation like
<t extends number></t>
, thenT
will be replaced withNumber
. - The compiler inserts type conversion code when necessary to ensure type safety.
For example:
List<String> list = new ArrayList<>(); list.add("hello"); String s = list.get(0);
After compilation, the actual bytecode becomes:

List list = new ArrayList(); list.add("hello"); String s = (String) list.get(0);
You can see that the generic information is erased and replaced by casting.
Impact of Type Erase
Since there is no generic information at runtime, this leads to some common restrictions or problems we have:
Generic arrays cannot be created : For example,
new T[10]
is not allowed because the runtime does not know whatT
is.You cannot use
instanceof
to determine generic types : for example,if (list instanceof List<String>)
is illegal.Method signature conflict : If the two methods are just generics, they will lead to compilation errors. For example:
public void method(List<String> list) {} public void method(List<Integer> list) {} // Compilation failed, method signature is repeated
These limitations all stem from the fact that Java generics only exist in the compilation stage .
How to bypass some limitations of type erasing?
Although Java erases the types, we can obtain some generic information in some ways:
Get generic information in the parent class by reflection : suitable for when subclasses inherit a parent class with generics.
class MyClass extends ArrayList<String> {} ParameterizedType type = (ParameterizedType) MyClass.class.getGenericSuperclass(); Type[] types = type.getActualTypeArguments(); // Get String.class
Save generic information using anonymous internal classes : This is how many frameworks (such as Gson) use them to parse generics.
Type type = new TypeToken<List<String>>(){}.getType();
This approach takes advantage of the ability of anonymous classes to retain their generic information when compiled.
Let's summarize
Type erasure is a compromise solution for Java to implement generics, bringing compatibility while sacrificing some flexibility. Understanding it will help avoid getting stuck in generic use and can better understand some of the design ideas of the underlying framework.
Basically that's it. If you encounter a strange problem when writing generic code, it is likely that type erasing is "making trouble".
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