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Table of Contents
How Do Binary Search Trees Work?
Implementing a Basic BST in Python
Common Operations: Search, Insert, Delete
Tips for Working with BSTs in Python
Home Backend Development Python Tutorial What are binary search trees in Python, and how do I implement them?

What are binary search trees in Python, and how do I implement them?

Jun 22, 2025 am 12:26 AM

Binary search trees (BSTs) is a data structure that supports efficient search, insertion and deletion operations. Its core mechanism is that the left subtree value of each node is smaller than the node value, and the right subtree value is larger than the node value. In terms of implementation, first define the Node class containing values ??and references to the left and right child nodes; secondly, implement the insertion function through recursion or iterative method; then implement the search function, and decide to search for the left or right subtree based on the comparison results; the deletion operation is more complicated, and it is necessary to deal with three situations: no child nodes, one child node and two child nodes, and two child nodes need to be found in the middle order and replaced; in addition, it is recommended to use recursion simplified implementation, use iteration when considering large trees to avoid stack overflow, and pay attention to testing the boundary situation and building a self-balancing tree to improve performance.

What are binary search trees in Python, and how do I implement them?

Binary search trees (BSTs) are a type of data structure that allows for efficient searching, insertion, and deletion of values. In Python, you can implement a BST using classes to represent nodes and the tree itself. They work by maintaining a specific ordering: for any given node, all values ??in its left subtree are less than the node's value, and all values ??in its right subtree are greater.

How Do Binary Search Trees Work?

At their core, BSTs are made up of nodes. Each node holds a value and references to its left and right children. The structure ensures that:

  • All values ??in the left subtree are less than the current node's value
  • All values ??in the right subtree are greater than the current node's value

This property makes searching and inserting more efficient compared to unordered structures like lists or arrays—especially as the dataset grows.

For example, when looking for a value, you don't need to scan everything. You just compare the target with the current node and decide whether to go left or right.

Implementing a Basic BST in Python

To create a BST from scratch, start by defining a Node class:

 class Node:
    def __init__(self, value):
        self.value = value
        self.left = None
        self.right = None

Then, manually insert nodes or build an insertion function:

 def insert(root, value):
    if root is None:
        return Node(value)
    if value < root.value:
        root.left = insert(root.left, value)
    else:
        root.right = insert(root.right, value)
    return root

You can use it like this:

 root = None
for val in [10, 5, 15, 3, 7]:
    root = insert(root, val)

This creates a BST where each insertion follows the left-right rule based on comparison.

Common Operations: Search, Insert, Delete

Here's how to implement these three basic operations.

Search

 def search(root, target):
    if root is None or root.value == target:
        return root
    if target < root.value:
        return search(root.left, target)
    return search(root.right, target)

Insert (as shown above)
Just keep comparing and moving left or right until you find a spot to place the new node.

Delete
This one is trickier because there are three cases:

  • Node has no children → just remove it
  • Node has one child → replace it with the child
  • Node has two children → find the inorder successor (smallest in the right subtree), copy its value, then delete the successor

Here's a simplified version:

 def delete(root, value):
    if root is None:
        return root
    if value < root.value:
        root.left = delete(root.left, value)
    elif value > root.value:
        root.right = delete(root.right, value)
    else:
        if root.left is None:
            return root.right
        elif root.right is None:
            return root.left
        temp = get_min_node(root.right)
        root.value = temp.value
        root.right = delete(root.right, temp.value)
    return root

And a helper to find the minimum node:

 def get_min_node(node):
    current = node
    While current.left:
        current = current.left
    Return current

Tips for Working with BSTs in Python

  • Use recursion for simplicity, especially for beginners.
  • For large trees, consider iterative approaches to avoid stack overflow.
  • Always test edge cases—like deleting the root or inserting duplicate values.
  • If you're building something serious, wrap everything into a BinarySearchTree class instead of managing the root separately.

Also, remember that not all BSTs are balanced. A skewed BST can degrade performance to O(n), similar to a linked list. If performance matters, look into self-balancing variants like AVL trees or red-black trees later.

Basically that's it.

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