Mac users may sometimes encounter a situation where a process occupies a port, which causes other applications or processes to be unable to use the port. If you encounter this situation, for example, when trying to use React.js, you find that a program is already running on port 3000, you can easily track the process that occupies the port through the command line.

We will show how to find and terminate a port-occupying process on MacOS.

How to find a process that occupies a port on a Mac

The syntax used is as follows: Replace PORTNUMBER with the process number you want to find the occupied port:

sudo lsof -i :PORTNUMBER

For example, find a process that occupies port 445:

sudo lsof -i :445

Or find a process that occupies port 3000: sudo lsof -i :3000

How to find and terminate a process that occupies a port on a Mac

Once you have obtained the PID (process ID) from the output of the lsof command, you can choose to exit the application, close the service, or terminate the process to release and unlock the occupied port.

The easiest way to terminate a process is to use the kill command:

kill -9 PID

For example, if the process ID that occupies port 3000 is "8384", you can use the following command:

kill -9 8384

If the process belongs to root, admin, or other users, you need to prepend sudo:

sudo kill -9 8384

It is worth mentioning that the lsof command used here is applicable on Mac and can also be used in Linux systems.

We assume that you have a certain understanding of the command line, and of course if not, you may not be here, and you will not be worried about which process occupies a specific port.

There are other ways to do this, but obviously we use the lsof command here, which is a very powerful tool, which can also be used to find processes that listen to TCP ports, find applications or processes that interact with specific files, find all processes that use internet connections, etc.

Are there any other ways to determine which process occupies a specific port? Please share your own solution in the comments below.

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