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<p>我開發(fā)了一個(gè) PHP 登錄/注冊腳本，當(dāng)用戶登錄時(shí)，它會(huì)啟動(dòng)一個(gè)會(huì)話并創(chuàng)建一個(gè) cookie，然后使用以下命令將用戶重定向到儀表板.php：</p> <pre class="brush:php;toolbar:false;">//get data in variables $emailAddress = mysqli_real_escape_string($conn,$_POST['emailAddress']); $password = mysqli_real_escape_string($conn,$_POST['password']); $remember = isset($_POST['rememberMe']); if(!filter_var($emailAddress, FILTER_VALIDATE_EMAIL)) { $error = 'Please enter a valid email address.'; } elseif(email_exists($emailAddress,$conn)) { // if email address exists $result = mysqli_query($conn,"SELECT password FROM users WHERE email = '$emailAddress'"); $retrievePassword = mysqli_fetch_assoc($result); if(!password_verify($password,$retrievePassword['password'])) // if password does not match { $error = 'Password is incorrect.'; } else { // if password correct, log user in $_SESSION['email'] = $emailAddress; if($remember == 'on') { // if "keep user logged in" was ticked setcookie("email",$emailAddress,time()+7200); // keep user logged in for 2 hours } header("location: dashboard.php"); } } else { // if email does not exist $error = 'Email address not registered.'; }</pre> <p>在我所有受限頁面（例如dashboard.php）的頂部，我有：</p> <pre class="brush:php;toolbar:false;">if(logged_in()) { // if user logged in, show page</pre> <p>logged_in() 函數(shù)是：</p> <pre class="brush:php;toolbar:false;">function logged_in(){ if(isset($_SESSION['email']) || isset($_COOKIE['email'])) { return true; } else { return false; } }</pre> <p>在數(shù)據(jù)庫中，我有一個(gè)標(biāo)題為 <code>usrUserTypeNo</code> 的列，其中管理員為“1”，普通用戶為“3”。 如何將此用戶類型合并到會(huì)話中，以便我可以根據(jù)用戶的角色確定向用戶顯示哪些內(nèi)容？</p>