利用stringify()方法，return underfined;可以過濾key為name的鍵，但是一下過濾了所有key為name的鍵，怎么控制只過濾company對(duì)象下面的name呢？
var person = {
name: "張三",
age: 14,
sex: "男",
tell: 5033453,
birthday:new Date(),
company:{
name:"百度",
contry:"中國(guó)",
boss:"馬化騰",
state:1
}
};
var jperson = JSON.stringify(person,function(key,value){
switch (key) {
case "name":
return undefined;
case "state":
return value===1?"通過":"未通過";
case "birthday":
return value.replace("T"," ").replace("Z","").substr(0,19);
default:
return value;
}
});
console.log(jperson);結(jié)果：{"age":14,"sex":"男","tell":5033453,"birthday":"2016-05-10 10:48:54","company":{"contry":"中國(guó)","boss":"馬化騰","state":"通過"}}
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擁有18年軟件開發(fā)和IT教學(xué)經(jīng)驗(yàn)。曾任多家上市公司技術(shù)總監(jiān)、架構(gòu)師、項(xiàng)目經(jīng)理、高級(jí)軟件工程師等職務(wù)。 網(wǎng)絡(luò)人氣名人講師，...
var?person?=?{
????name:?"張三",
????age:?14,
????sex:?"男",
????tell:?5033453,
????birthday:new?Date(),
????company:{
????????name:"百度",
????????contry:"中國(guó)",
????????boss:"馬化騰",
????????state:1
????}
};
var?jperson?=?JSON.stringify(person,function(key,value){
????switch?(key)?{
????????case?"company":
????????????delete?value["name"];
????????????return?value;
????????case?"state":
????????????return?value===1?"通過":"未通過";
????????case?"birthday":
????????????return?value.replace("T","?").replace("Z","").substr(0,19);
????????default:
????????????return?value;
????}
});
console.log(jperson);
