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<p>我有一個(gè)關(guān)於以下程式碼的問題。 <em>console.log</em> 的輸出為：</p> <p>我透過JavaScript的Ajax請(qǐng)求請(qǐng)求的URL是「login.php」：</p> <pre class="brush:php;toolbar:false;"><?php include('init.php'); use LoginLoginService; #include(__DIR__.'/Login/LoginService.php'); global $pdo; session_start(); $username = $_POST['username']; $pass = $_POST['password']; if (!empty($username)) { $test = new LoginService(); $user = $test->getUsersLogin($username); if (!empty($user) && $user[0]['login'] == $username) { $json = json_encode(array("success" => 1)); echo $json; } else { $json = json_encode(array("success" => 0)); echo $json; } } ?></pre> <p>我的JavaScript的Ajax請(qǐng)求：</p> <pre class="brush:php;toolbar:false;">$(() => { $('.login-form').on('submit', function (e) { e.preventDefault(); $.ajax({ type: "POST", dataType: "json", timeout: 500, url: '/src/login.php', data: $(this).serialize(), success: (data) => { try { var jso = JSON.parse(data); console.log(jso); } catch (e) { console.log(e); return false; } }, error: (data) => { console.log(JSON.parse(data)); } }); }); });</pre> <p>為什麼PHP的回應(yīng)<code>{"success":1}</code>不正確？問題是什麼？ </p> <blockquote> <p>SyntaxError: “[object Object]”不是有效的JSON</p> </blockquote><p><br /></p>

myFunction(data: string) {
  try {
    JSON.parse(data); 
    console.log(data);
  }
   catch (e) {
   console.log(e); 
  }
}

var jso = JSON.parse(data); console.log(jso);

console.log(data);