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目錄
Detect Gaps in a Numeric Sequence
Example
Handle Sequential Gaps or Single Missing Values
For Date Sequences
首頁 資料庫 SQL 如何在 SQL 中查找序列中間隙的開始和結(jié)束

如何在 SQL 中查找序列中間隙的開始和結(jié)束

Oct 12, 2025 am 02:18 AM

使用窗口函數(shù)LEAD找出序列中的間隙。首先按值排序,比較當(dāng)前值與下一個(gè)值,若差值大於1,則存在間隙。例如數(shù)據(jù)1,2,5,6,10會(huì)返回兩段間隙:3到4和7到9。對(duì)於日期序列,可用INTERVAL進(jìn)行日期運(yùn)算,方法類似。

How to find the start and end of a gap in a sequence in SQL

To find the start and end of a gap in a sequence using SQL, you can use window functions to identify missing values. This is commonly useful when dealing with auto-incremented IDs, dates, or any ordered numeric sequence where gaps indicate missing entries.

Detect Gaps in a Numeric Sequence

Assume you have a table sequence_table with a column value , and you want to find where numbers are missing.

The idea is to compare each number with the next one. If the difference is greater than 1, a gap exists.

Here's how to do it:

WITH ordered_values AS (
  SELECT value, LEAD(value) OVER (ORDER BY value) AS next_value
  FROM sequence_table
),
gaps AS (
  SELECT 
    value 1 AS gap_start,
    next_value - 1 AS gap_end
  FROM ordered_values
  WHERE next_value IS NOT NULL 
    AND next_value - value > 1
)
SELECT gap_start, gap_end FROM gaps;

This query returns all gaps: from gap_start to gap_end .

Example

If your data has values: 1, 2, 5, 6, 10

The output will be:

  • gap_start = 3, gap_end = 4
  • gap_start = 7, gap_end = 9

Handle Sequential Gaps or Single Missing Values

If you're only interested in single missing numbers (gaps of size 1), filter where gap_start = gap_end .

To find only those:

SELECT gap_start AS missing_value
FROM gaps
WHERE gap_start = gap_end;

For Date Sequences

If working with dates (eg, daily records), replace arithmetic with DATEADD or interval logic depending on your database.

Example in PostgreSQL:

WITH ordered_dates AS (
  SELECT date_col, 
         LEAD(date_col) OVER (ORDER BY date_col) AS next_date
  FROM date_table
),
gaps AS (
  SELECT 
    date_col INTERVAL '1 day' AS gap_start,
    next_date - INTERVAL '1 day' AS gap_end
  FROM ordered_dates
  WHERE next_date IS NOT NULL 
    AND next_date > date_col INTERVAL '1 day'
)
SELECT gap_start, gap_end FROM gaps;

Basically, the method relies on ordering the sequence and checking the difference between consecutive entries. Adjust based on your data type and SQL dialect.

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