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? ??? ??? MySQL ???? SQL Server?? ?? ??? ??? ?? ?? ??? ????? ???? ??? ??????

SQL Server?? ?? ??? ??? ?? ?? ??? ????? ???? ??? ??????

Jan 10, 2025 am 11:56 AM

How to Efficiently Generate a Date Range for Multiple Guest Registrations in SQL Server?

SQL Server?? ??? ?? ?? ??? ????? ??

?? ??? ????? ???? ??? ? ???? ??? ???? ?? ????? ?? ???? ???? ????? ??? ????? ????. ? ??? ??? ??? ?? ???? ???? ???? ???? ??? ?????.

?? ?? ??? ??

ROW_NUMBER() ??? ???? ???? ? ?? ??? ?? ??? ???? ?????. ?? ???? ??? ?? ???? ???? ??? ?? ??? ?????. 

DECLARE @start DATE, @end DATE;
SELECT @start = '20110714', @end = '20110717';

;WITH n AS 
(
  SELECT TOP (DATEDIFF(DAY, @start, @end) + 1)
    n = ROW_NUMBER() OVER (ORDER BY [object_id])
  FROM sys.all_objects
)
SELECT 'Bob', DATEADD(DAY, n-1, @start)
FROM n;

?? ???? ??

? ??? ?? ????? ????? ?? ??? ??? ? ????. 

DECLARE @t TABLE
(
    Member NVARCHAR(32),
    RegistrationDate DATE,
    CheckoutDate DATE
);

INSERT @t SELECT N'Bob', '20110714', '20110717'
UNION ALL SELECT N'Sam', '20110712', '20110715'
UNION ALL SELECT N'Jim', '20110716', '20110719';

;WITH [range](d,s) AS 
(
  SELECT DATEDIFF(DAY, MIN(RegistrationDate), MAX(CheckoutDate))+1, MIN(RegistrationDate) 
  FROM @t 
),
n(d) AS
(
  SELECT DATEADD(DAY, n-1, (SELECT MIN(s) FROM [range]))
  FROM (SELECT ROW_NUMBER() OVER (ORDER BY [object_id]) 
  FROM sys.all_objects) AS s(n)
  WHERE n <= (SELECT d FROM [range])
)
SELECT t.Member, n.d
FROM @t t
INNER JOIN n ON n.d BETWEEN t.RegistrationDate AND t.CheckoutDate;

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